protected function EasyRdf_Sparql_Result::parseJson

Parse a SPARQL result in the JSON format into the object.

@ignore

File

drupal/core/vendor/easyrdf/easyrdf/lib/EasyRdf/Sparql/Result.php, line 338

Class

EasyRdf_Sparql_Result

Class for returned for SPARQL SELECT and ASK query responses.

Code

protected function parseJson($data) {

  // Decode JSON to an array
  $data = json_decode($data, true);
  if (isset($data['boolean'])) {
    $this->type = 'boolean';
    $this->boolean = $data['boolean'];
  }
  elseif (isset($data['results'])) {
    $this->type = 'bindings';
    if (isset($data['head']['vars'])) {
      $this->fields = $data['head']['vars'];
    }
    foreach ($data['results']['bindings'] as $row) {
      $t = new stdClass();
      foreach ($row as $key => $value) {
        $t->{$key} = $this
          ->newTerm($value);
      }
      $this[] = $t;
    }
  }
  else {
    throw new EasyRdf_Exception("Failed to parse SPARQL JSON Query Results format");
  }
}